(x)^2/2=5x

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Solution for (x)^2/2=5x equation: 


x in (-oo:+oo)

(x^2)/2 = 5*x // - 5*x

(x^2)/2-(5*x) = 0

(x^2)/2-5*x = 0

1/2*x^2-5*x = 0

DELTA = (-5)^2-(0*1/2*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+5)/(1/2*2) or x = (5-25^(1/2))/(1/2*2)

x = 10 or x = 0

x in { 0, 10 }

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